Monday, 19 November 2012

(6) Linear Equation - Persamaan Linear

Linear Equation | Persamaan Linear | simultaneous linear equation | persamaan serentak |

23 comments:

  1. bagaimana nak selesaikan..??

    2x + y = 1 (1)
    x + y - 2 ( 2)

    ReplyDelete
    Replies
    1. 2x + y = 1 (1)
      x + y = 2 (2)

      Step 1 :
      y = 2- x (3)

      Step 2 :
      Masukkan persamaan (3) dalam persamaan (1)
      2x + (2-x) = 1
      x + 2 = 1
      x = -1 (4)

      Step 3:
      Masukkan persamaan (4) dalam persamaan (3)
      y = 2 - (-1)
      = 3

      Delete
  2. bagaimana nak selesaikan..??

    2x + y = 1 (1)
    x + y - 2 ( 2)

    ReplyDelete
    Replies
    1. 2x + y = 1(1)
      x + y = 2(2)

      2x + 2y = 4(2)
      2x + y = 1

      2y + Y = 8 + 1
      3y = 9
      y = 9/3
      y = 3

      x + y = 2(2)
      x + 3 = 4
      x = 4-3
      x = 1

      y = 3, x = 1

      Delete
  3. bagaimana nak selesaikan

    -18-(-15)+x=0

    ReplyDelete
  4. -18 + 15 + x = 0
    -3 + x = 0
    x = 0 + 3
    x = 3

    ReplyDelete
  5. Macam mana nak selesaikan persamaan y=px^2+x+q kepada persamaan linear?

    ReplyDelete
  6. Bagaimana nk selesaikan
    (3x-4)-(8x-1)=11x-3

    ReplyDelete
    Replies
    1. 24x - 32x -3 + 4= 11x - 3
      -8x + 1 = 11x - 3
      1 + 3 = 11x + 8x
      4 = 19x
      19x = 4
      x = 4/19

      Delete
  7. Example 2 tu ade yg slh -2 -2y=6 sptutnye -2+2y=6

    ReplyDelete
  8. Macamana nak selesaikan

    5/6x - y = 12 -1
    5x - 4y = 52 -2

    ReplyDelete
  9. 3x + 4 =19
    MCM mana nk selesaikan

    ReplyDelete
  10. -p + 4r = 4 dan -4p + 3r = -10
    Cari nilai r

    ReplyDelete
  11. selesaikan persamaan linear
    y-4=-11

    ReplyDelete
  12. bagaimana hendak selesaikan 1) 3(x+2)+4=4
    2) 2(2x-3)-2=8
    3) 4(x+2)-6=18
    4) 3x/4 -2=7
    5) 2y/5+4=8
    6) 2x/3-4=2
    7) 2(x+4)/3=8
    8) 4(x-5)/3=12
    9) 3(x+4)/4=6

    ReplyDelete
  13. dalam satu kuiz matematik,Raju dapat 13 markah kurang daripada kumar manakala geetha mendapat dua kali markah kumar jika jumalah markah mereka ialah 67. cari markah diperoleh raju

    ReplyDelete
    Replies
    1. sekarang ada 13 x 3 extra marks
      so sisihkan 13 x 3=67-39
      =28
      sekarang ni markah bassic geetha 2x1 kumar + 1 raju
      so bahagi 4=28 bahagi 4 = 7
      7=raju
      7+13= 20=kumar
      20x2=40= geetha

      Delete
  14. tolonglah jawab yang atas tu ye

    ReplyDelete

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